Question 45231
THE STANDARDS FORMULA FOR A LINE IS Y=mX+b where X & Y ARE TWO POINTS THROUGH WHICH THE LINE PASSES THROUGH. IN YOUR CASE THE FORMULA FOR THIS LINE IS Y=2/3X-2

m IS THE VALUE OF THE SLOPE OF THE LINE. b IS THE Y INTERCEPT VALUE.
TO FIND THE AT LEAST TWO POINTS OF THIS LINE SET X=0 AND SOLVE FOR Y. THEN SET Y=0 AND SOLVE FOR X.

THUS YOU GET 0=2/3X-2 OR 2/3X=2 OR X=2*3/2 OR X=3 (3,0)
Y=2/3*0-2 OR Y=0-2 OR Y=-2 (0,-2)