Question 433053
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Hi
{{{sqrt(y+10)= (y-2)}}}
    y + 10 = y^2-4y+4
    y^2 -5y -6 = 0
factoring
   (y-6)(y+1) = 0
  Note:SUM of the outside terms(y) and the inside terms(-6y) = -5y  
   (y-6) = 0   {{{ y =highlight( 6)}}}
   (y+1) = 0    y = -1  |Extraneous, cannot use sqrt(9)&#8800; -3 

CHECKING our Answer*** 
    {{{sqrt(16) = 6-2 = 4}}}