Question 432974
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Hi
Let x and (x+2)represent the two consecutive odd integers
Question states***
 x^2 - (x+2) = 28
 x^2 -x -30 = 0
factoring
(x-6)(x+5) = 0
(x-6)= 0    x = 6  |Toss out this solution as it is not an odd number
(x+5) =0    x = -5   the two consecutive odd integers are -5,-3
 
CHECKING our Answer***
  25 -(-3) = 28