Question 432839
 4 minus radical 3 over 7... rationalize the numerator 
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(4-sqrt(3))/7
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Multiply numerator and denominator by (4+sqrt(3))
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= [(4-sqrt(3))(4+sqrt(3))]/[7(4+sqrt(3))]
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= [16-3]/[28+7sqrt(3)]
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= 13/[28+7sqrt(3)]
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Cheers,
Stan H.