Question 432385
determine k so that the first polynomial is a factor of the second.
 x+2; {{{ 2x^3 + 3x^2 + k }}} 
:
Use synthetic division, we have to put a zero in the x position
:
_________________________
-2|2 + 3 + 0 + k
......... - 4 + 2 - 4
.....---------------
..... 2 - 1 + 2 + 0
from this we have the equation 
k - 4 = 0
k = 4
Then the equation is: 2x^3 + 3x^2 + 4, which is :(x+2) (2x^2 - x + 2)
:
:
 x-2; {{{ x^4 - 2x^3 +kx+ 6 }}}
:
Use synthetic division, we have to put a zero in the x^2 position
:
_________________________
+2|1 - 2 + 0 + k + 6
......... +2 + 0 + 0 + 2k
.....--------------------
..... 1 + 0 + 0 + k  + 0
from this we have the equation 
2k + 6 = 0
2k = -6
k = -3
:
The equation: x^4 - 2x^3 - 3x + 6; which is (x-2)*(x^3 - 3x)