Question 432648
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Hi
*[tex \LARGE \ \ \ \ \ \ \ \ \ \ log_b(x) \ = \ y \ \ \Rightarrow\ \ b^y = x]
  Log 3(x-2)= -1
     3^-1 = (x-2)
       1/3 = (x-2)
        1 = 3(x-2)
        7 = 3x
         x = 7/3