Question 432597
If the length of a rectangle is 4 in. more than a square,then its' length is x+4.  Similarly, its' width is x+2.  The sum of the areas, rectangle and square, is 64:
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(x+2)(x+4)+x2=64
x2+6x+8+x2=64
2x2+6x-56=0
(2x+14)(x-4)=0
x=-7,4
Throwing out the negative result, our square is 4X4 inches.*[invoke quadratic "x", 2, 6, -56 ]