Question 432634
A){{{sqrt(8x^2y) * sqrt(2xy)}}}
{{{sqrt(8x^2y*2xy)}}}
{{{sqrt(16x^3y^2)}}}
{{{sqrt(16) * sqrt(x^2*x) * sqrt(y^2)}}}
{{{4 * x *sqrt(x) * y}}}
{{{4xy * sqrt(x)}}}

B) the conjugate is the same pair of terms with the sign changed
Given
{{{4sqrt(2) - 2*sqrt(3)}}} 
the conjugate is
{{{4sqrt(2) + 2*sqrt(3)}}}