Question 432561
From the quadratic formula, the roots are:
{{{x = (-b + sqrt(b^2 - 4ac))/2a}}} and {{{x = (-b - sqrt(b^2 - 4ac))/2a}}}
These can be written as {{{-b/2a + sqrt(b^2-4ac)/2a}}} and {{{-b/2a - sqrt(b^2-4ac)/2a}}}
Summing the two roots gives:
{{{-b/2a - b/2a}}} = {{{-b/a}}}