Question 432424
If we can use "any" operation then we can easily create new algebras and new operations, such as S({{{a[1]}}}, {{{a[2]}}}, ..., {{{a[n]}}}) = n!, the number of ways to arrange a distinguishable n objects in a line. If we "assume" the 0's are distinguishable, then S(0,0,0,0,0,0) = 6! = 720.