Question 432483
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Hi
starting with $100 and adding $3 every year: Amount after 't years':
a(t)=100+3t
a(0)=100+3t = 100+3*0 = $100
a(5)=100+3t = 100 + 3*5 = $115
etc...
a(10)=100+3t 
a(30)=100+3t