Question 432421
As you know this quadratic function represent a downward parabola.

First, we have to find the standard form by completing the square.

{{{y=-4(x^2-3x)-5=-4(x^2-3x+9/4)+9-5=-4(x-3/2)^2+4}}},Finally we get:

{{{y=-4(x-3/2)^2+4}}}, that represent a parabola with vertex (3/2, 4) and axis of 

symmetry x=3/2.

{{{graph(300, 300, -10, 10, -10, 10, -4x^2+12x-5)}}}