Question 432361
{{{abs(matrix(3,3, 6a, 3b, 15c, 2l, m,5n,2p, q, 5r))

= 2*5*abs(matrix(3,3, 3a, 3b, 3c, l, m,n,p, q, r))
}}}, after factoring 2 from the 1st column, and 5 from the 3rd column.
= {{{2*5*3*abs(matrix(3,3, a, b, c, l, m,n,p, q, r))}}}, after factoring 3 from the 1st row.
Hence the value of the determinant is 2*5*3*2 = 60.