Question 432348
Assuming {{{x > 0}}} and {{{x<>1}}}, (the parameters for the logarithmic base), the expression {{{log(x, b)}}} is one-to-one, and so by property of inverses, 
{{{log(x,9) = log(x, 6)}}} <==> {{{x^log(x,9) = x^log(x,6)}}}, or 9=6, which is false.  Hence the equation has no real solution.