Question 432251
"What is the slope of any line perpendicular to the line formed by the equation 
-7x + 63y = 9?"


Slope-intercept form is y = mx + b
m is the slope
b is the y-intercept


-7x + 63y = 9
63y = 7x + 9 {added 7x to both sides}
y = (1/9)x + 1/7 {divided both sides by 63}
slope = 1/9


Perpendicular lines have slopes which are negative reciprocals.


If the slope of this line is 1/9,
the perpendicular line would have a slope of -9.


-9 is the answer
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