Question 432152
Let length = x, width = y

perimeter = 2(x+y) = 6

and area = x*y = 2


as, 2(x+y) = 6

=> x+y = 3

=> x = 3-y

after putting the value of x on   x*y = 2

we get  (3-y)y= 2

=> y^2 -3y +2 =0

=> (y-1)(y-2) = 0     after factorizing 

so, y = 1 or 2

if y =1, x =2

y = 2, x =1


so, its dimensions are  2 and 1.