Question 432154

let number is x.

( 2/x^2) - (3/x)  = -1

=> ( 2 -3x) = -x^2

=> x^2 -3x + 2 = 0

=>  x^2 -x -2x + 2 = 0

=> x(x-1) -2(x -1) = 0

=> (x-1)(x-2) = 0

=> x= 1 or 2 .


so, numbers are 1 and 2.