Question 431702
(x-5)(x+5)(x-1)(x+1)=0
is mostly right. It should be:
P(x) = (x-5)(x+5)(x-1)(x+1)<br>
All that is left is to multiply out the right side. I'd suggest mulitplying the first two factors and the last two factors first. For these we can use the {{{(a+b)(a-b) = a^2-b^2}}} pattern to multiply quickly:
{{{P(x) = (x^2 - 5^2)(x^2 - 1^2)}}}
or
{{{P(x) = (x^2 - 25)(x^2 - 1)}}}
Now just use FOIL to multiply the remaining factors.