Question 431957
{{{4x^2 + 14x = 0}}}
Dividing both sides by 2:
{{{2x^2 + 7x = 0}}}
Factor out what is common (x):
{{{(x)(2x + 7) = 0}}}
.
Set EACH term within parentheses to zero to find the possible values of x:
x = 0 (one possible solution)
.
2x+7 = 0
2x = -7
x = -7/2 (another possible solution)
.
therefore:
x = {-7/2, 0}  (solution set)