Question 431949
SOLVE BY SUBSTITUTION METHOD :)

x+4=-1/2+4x

4+1/2 = 4x-x

9/2 = 3x or x= 3/2

SUBTITUTE VALUE OF x 

2x+3y=1/2x+2y+1

2*3/2 + 3y = 1/(2*3\2)+2y+1

3+3y = 1/3+2y+1

3y-2y = 1/3+1-3

y = 1/3-2 = -5/3

solve by ADDITION METHOD  :)

3Y-1 divided by 2= 3x+8 divided by 5
x+y divided by 2= 6+x-y divided by 2

(3y-1)/2 = (3x+8)/5

or 5(3y-1) = 2(3x+8)

15y-5 = 6x+16

or 6x-15y = -21------------(1)

(x+y)/2 = (6+x-y)/2 or (x+y) = (6+x-y)

2y = 6 or y = 3
put value of y in (1) and get x