Question 431851
{{{1+ 1/x^2 = 3/x}}}

{{{ 3/x -1/x^2= 1}}}
LCD = x^2
{{{(3x-1)/x^2 =1}}}

3x-1= 1*x^2
3x-1=x^2

x^2-3x+1=0


Find the roots of the equation by quadratic formula								
								
a=	1	b=	-3	c=	1			
								
b^2-4ac=9-4					
b^2-4ac=5 ,  {{{sqrt(5)}}}=2.24	
{{{x=(-b+-sqrt(b^2-4ac))/(2a)}}}								
{{{x1=(-b+sqrt(b^2-4ac))/(2a)}}}								
x1=(3+2.24)/2			
x1=2.62							
x2=(3-2.24)/2				
x2=0.38