Question 431736
5y+3x=10
5y= -3x+10
/5
y= -3x/5 +2..............1

3y-5x=6  
3y=5x+6
/3
y=5x/3+2

You find that the slopes of these two lines are negative reciprocal of each other. m1*m2=-1

3	x	+	5	y	=	10	.............1	
-5	x	+	3	y	=	6	.............2	
Eliminate y								
multiply (1)by 		-3						
Multiply (2) by		5						
-9x-15y=-30		
-25x+15y=30		
Add the two equations								
-34x=0		
/-34							
x=0		
plug value of x	in (1)				
3x+5y=10		
5y=10		
5	y	=	10
5	y	=	10		
y	=	2   

They intersect at (0,2)

{{{graph(300,300,-10,10,-10,10,y=(-3x/5)+2,y=(5x/3)+2))}}}