Question 431612
by Pythagoras ___ x^2 + (2x+8)^2 = (3x-8)^2


x^2 + 4x^2 + 32x + 64 = 9x^2 - 48x + 64


0 = 4x^2 - 80x


0 = x^2 - 20x


0 = x(x - 20)


x = 0


x - 20 = 0 ___ x = 20