Question 431399
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Hi
Sqrt(2x-x^2)=(x-1)^2
   (2x-x^2) = (x-1)^4      |{{{(a + b)^4 = a^4 + 4a^3b + 6a^2b^2 + 4ab^3 + b^4}}}   
  2x-x^2 = x^4 + 4x^3*-1 + 6x^2*1 + 4x*-1 + 1
  2x-x^2 = x^4 - 4x^3 + 6x^2 - 4x + 1
       x^4 - 4x^3 + 7x^2 -6x + 1 = 0