Question 431319
6x^2+12x +5=0

Find the roots of the equation by quadratic formula							
							
a=	6	,b=	12	,c=	5		
							
b^2-4ac=144-120				
b^2-4ac=24						
{{{x=(-b+-sqrt(b^2-4ac))/(2a)}}}							
{{{x1=(-b+sqrt(b^2-4ac))/(2a)}}}							
{{{x1=(-12+sqrt(24))/(12)}}}					
x1=(-12+4.9)/12
x1=	-0.59				
x2=(-12-4.9) /12	
x2= 	-1.41