Question 431268
{{{y - 5 = ((5--20)/(3--2))(x-3)}}}
==> y-5 = 5(x-3)
==> y - 5 = 5x - 15
or y = 5x - 10.

You could also use {{{y --20 = ((5--20)/(3--2))(x--2)}}}, and still get the same equation in the end.