Question 431081
  <pre><font face = "Tohoma" size = 4 color = "indigo"><b> 
Hi
y= -2x^2-6x+5
1)parabola opening downward
y=-2(x+3/2)^2 +19/2
2) vertex Pt(-1.5,9.5)
3) cross the y-axis at Pt(0,9.5)
4) Axis of symmetry is x = -1.5
5) 9.5 is the maximum value of y when x = 1.5
6) x = -3/2 ħsqrt(4.75) are the solutions    | (x+3/2) = ħsqrt(19/4)
7) x-intercepts are (.679,0) and (-3.68,0)
{{{drawing(300,300, -15,15,-15,15,  blue(line(-1.5,15,-1.5,-15))  , grid(1),
circle(-1.5, 9.5,0.5),
circle(-3.68, 0,0.5),
circle(+.679, 0,0.5),
graph( 300, 300, -15,15,-15,15,0,-2x^2-6x+5
 ))}}}