Question 430988
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Hi, 
You did not state the exact nature of your Question:
h=-16t^2+96t+112   |Represents a parabola opening downward
h= -16(t-3)^2 + 144 + 160 |completing Square to find Vertex
the vertex form of a parabola, {{{y=a(x-h)^2 +k}}} where(h,k) is the vertex
 Vertex(3,304)  h reaches a maximum of 304 when t = 3