Question 430903
If g(x) varies directly as {{{x^2}}}, then we can write g(x) as:
{{{g(x) = kx^2}}} where {{{k}}} is a constant.
Given {{{g(5) = 50}}}, we can find {{{k}}}
{{{50 = k(5)^2 -> k = 2}}}
So the function is {{{g(x) = 2x^2}}}
Here is the graph:
{{{graph(300,300,-10,10,-30,30,2*x^2)}}}