Question 430840
Solve for x in the equation: (1+sinx)/cosx + cosx/(1+sinx) = 4 for 0<=x<=2pi rads 
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 (1+sinx)/cosx + cosx/(1+sinx) = 4
LCD: (cosx)(1+sinx)
(1+sinx)^2+cos^2x=4(cosx)(1+sinx)
1+2sinx+sin^2x+cos^2x=4(cosx)(1+sinx)
sin^2x+cos^2x=1
2+2sinx=4(cosx)(1+sinx)
2(1+sinx)=4(cosx)(1+sinx)
2=4(cosx)
cosx=2/4=1/2
x=pi/3 and 5pi/3 (note: cos positive in quadrants I and IV)