<PRE><B>Question 430627</B>
 (7x+2)^2-5x[-3(x+2)] 
Once I factor what is inside the brackets do I keep it in the brackets then distribute the -5x to what is inside the brakcets?
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(7x+2)^2-5x[-3x-6]
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(7x+2)^2+15x^2+30x
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49x^2+28x+4 + 15x^2+30x
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64x^2+58x+4
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Cheers,
Stan H.</PRE>