<PRE><B>Question 430517</B>
find the equation of the axis of symmetry and the coordinates of the vertex of the graph of the function.
y=4x^2+5x-1
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Complete the square:
4x^2+5x = y+1
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4(x^2+(5/4)x+(5/8)^2) = y+1+4(5/8)^2
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4(x+(5/8))^2 = y + (16/16)+(25/16)
(x+(5/8))^2 = (1/4)(y+(41/16))
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Vertex: (-5/8 , -41/16)
Axis: x = -5/8
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Graph:
{{{graph(400,300,-10,10,-10,10,4x^2+5x-1)}}}
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Cheers,
Stan H.</PRE>