Question 430405
Find the x-intercepts and the y-intercepts for f(x). 
f(x)= x^2-9x+9
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Two rules to remember: 
 1)To find the y-intercept, set x=0, then solve for y.
 2)To find the x-intercept, set y=0, then solve for x.
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Finding y-intercept, set x=0
y-intercept=0-0+9=9 (ans)
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Finding x-intercept, set y=0
0=x^2-9x+9
solve by quadratic formula below:
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{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
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a=1, b=-9, c=9
x=[-(-9)+-sqrt(81-4*1*9)]/2
x=(9+-sqrt(45))/2
x=(9+-6.7)/2
x=15.7/2 or 2.3/2
x=7.85 or 1.15 (ans)