Question 430255
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Hi
Survey Results reveal that 45% of patients screened for a virus test positive
 p = .45  q = .55 
random sample of 35 patients
mean = .45*35 = 16 expected average number to test positive..
SD = sqrt(35*.55*.45) = ~3
P(9 test positive)is less than 2 SD left of mean ..very small probability < .02

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