Question 430231
I need help with a few Algebra problems, please.
If the discriminant in the quadratic formula is a perfect square, then the quadratic equation will have _____________solution(s).e dis
If the discriminant is negative there are 2 complex unequal solutions.
If the discriminant is zero there are 2 Real equal solutions.
If the discriminant is positive there are 2 Real unequal solutions.
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Solve the quadratic formula. Simplify the answer.
x^2 - 3x - 1 = 0
x = [3 +- sqrt(9-4*-1)]/2
x = [3 +- sqrt(13)]/2
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4x^2 + x - 1 =0
x = [-1 +- sqrt(1-4*4*-1)]/8
x = [-1 +- sqrt(17)]/8
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Cheers,
Stan H.