Question 430027
a. (n2 – 5n + 3)(n2 + n – 1)
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= n^2(n^2+n-1) -5n(n^2+n-1) + 3(n^2+n-1)
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= n^4+n^3+n^2 - 5n^3-5n^2+5n + 3n^2+3n-3
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= n^4+n^3-n^2+8n-3
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b. (4a3b2)^3 (3ab4)^2 
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= (64a^12b^6)(9a^2b^8)
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= 576a^14b^14
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Cheers,
Stan H.
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