Question 430094
5x+7y=-23_-3x+y=19

Since -3x does not contain the variable to solve for, move it to the right-hand side of the equation by adding 3x to both sides.
5x+7y=-23_y=3x+19

Replace all occurrences of y with the solution found by solving the last equation for y.  In this case, the value substituted is 3x+19.
5x+7(3x+19)=-23_y=3x+19

Multiply 7 by each term inside the parentheses.
5x+21x+133=-23_y=3x+19

Since 5x and 21x are like terms, add 21x to 5x to get 26x.
26x+133=-23_y=3x+19

Since 133 does not contain the variable to solve for, move it to the right-hand side of the equation by subtracting 133 from both sides.
26x=-133-23_y=3x+19

Subtract 23 from -133 to get -156.
26x=-156_y=3x+19

Divide each term in the equation by 26.
(26x)/(26)=-(156)/(26)_y=3x+19

Simplify the left-hand side of the equation by canceling the common factors.
x=-(156)/(26)_y=3x+19

Simplify the right-hand side of the equation by simplifying each term.
x=-6_y=3x+19

Replace all occurrences of x with the solution found by solving the last equation for x.  In this case, the value substituted is -6.
x=-6_y=3(-6)+19

Multiply 3 by each term inside the parentheses.
x=-6_y=-18+19

Add 19 to -18 to get 1.
x=-6_y=1

This is the solution to the system of equations.
x=-6_y=1