Question 430003
We are given x = 2 is one of the zeros, so we know that x - 2 is one of the factors of the polynomial 
We can divide the polynomial by x - 2 to get a quadratic:
x^3-4x^2+21x-34/x-2 
Performing the division gives {{{x^2 - 2x + 17}}}
Now use the quadratic formula to get the other two zeros:
{{{x = (2 +- sqrt(4 - 68))/2}}}
The other two roots are complex, and are equal to:
x = 1 + 4i, and x = 1 - 4i