Question 430003
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Hi
 Given the zero: x=2, of the polynomial: x^3-4x^2+21x-34=0, find the others.

 x^3-4x^2+21x-34 = (x-2)(x^2 - 2x + 17)
 x^2 - 2x + 17 = 0    |Using standard form: ax^2+bx +c = 0
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} 
{{{x = (2 +- sqrt( -64 ))/(2) }}}
 {{{x = (2 +- 8i)/(2) }}} 
    x = 1 + 4i
and x = 1 - 4i