Question 429937
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Hi
Let x represent how much pure salt needs to added to make 100lb of 24% solution
Question states***
"making a  100lb   24% solution 
 1.0x + .05*(100-x)= .24*100
        .95x = .19*100
          x = 20 lb of pure salt need to be added.
CHECKING our Answer***
 1.0*20lb + .05*80lb = 20lb + 4lb = .24*100 = 24 lbs (pure salt)