Question 429816
A soda machine contains $3.00 in nickels and dimes. If the number of dimes is 5 more than twice the number of nickels, how many coins of each type are there?
n = # of nickels
d = # of dimes
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Write down what's given.  Don't whine about "word problems"
"Two plus two" is a word problem.
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d = 2n + 5 - # of dimes = 2 times # of nickels plus 5
5*n + 10*d = 300 - n's are 5 cents each, and dimes are 10 cents each.  See that?
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d = 2n + 5
5*n + 10*d = 300
Now it's not a word problem.