<PRE><B>Question 429778</B>
When two times the square of a number is decreased by seven times the same number, the result is 15. Find the number. 
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Equation:
2x^2-7x = 15
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2x^2-7x-15 = 0
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Factor:
2x^2-10x+3x-15 = 0
2x(x-5)+3(x-5) = 0
(x-5)(2x+3) = 0
x = 5 or x = -3/2
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Cheers,
Stan H.</PRE>