Question 429718
Solve:The first step is to factor the equation:

{{{t(t^4-16^2)=t(t^2-16)(t^2+16)=t(t-4)(t+4)(t^2+16)}}}, rewrite the equation:

{{{t(t-4)(t+4)(t^2+16)=0}}} This product is equal to zero if:

t=0, t-4=0 => t=4, t+4=0 => t=-4. ({{{t^2+16}}}, is always different from zero).

So, the real roots of this equation is the set {-4, 0, 4}.

Done.