Question 429580
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Hi
{{{8x^2 /(x^2-9)*( x2 + 6x + 9)/ (16x^3)}}}
CANNOT have a ZERO in the demonimator
16x^3 &#8800; 0   x &#8800; 0
x^2-9 = (x+3)(x-3) &#8800; 0  |x &#8800; -3 and x &#8800; 3
Domain {x| x &#8800; 0 and x &#8800; 3 and x &#8800; -3} 
 Which says x can be any real number with the exception of the values listed