Question 429571
Solve:{{{3/(2x+1)-(x+1)/(4x^2-1)}}}=, (Step 1: Factor the denominator).

{{{3/(2x+1)-(x+1)/(2x+1)(2x-1)}}}=, (Step2: Find LCD and not allowed values of x.)

The LCD is (2x+1)(2x-1)=0, 2x+1=0 => x=-1/2 and 2x-1=0 => x=1/2

{{{(3(2x-1)/(2x+1)(2x-1))-(x+1)/(2x+1)(2x-1)}}}=,( Multiply the numerator and 

denominator of the first term by (2x-1)).

{{{(3(2x-1)-(x+1))/(2x-1)(2x+1)}}}=( As sum of terms with same denominator).

{{{(6x-3-x-1)/(4x^2-1)}}}=, (Using distributive property.Combine like terms.)

{{{(5x-4)/(4x^2-1)}}}.

Done.