Question 429559
{{{(sin(beta) + cos(beta))^2 = (sin(beta))^2 + (cos(beta))^2 + 2 sin(beta) cos(beta)}}}
We can use the two identities: 
{{{(sin(beta))^2 + (cos(beta))^2 = 1}}}
{{{2sin(beta) cos(beta) = sin(2*beta)}}}
So the expression simplifies to:
{{{1 + sin(2*beta)}}}