Question 429451
Solution:We know that: {{{(sin(theta))^2+(cos(theta))^2=1}}} 

{{{(cos(theta))^2=1-(sin(theta))^2=1-(1/3)^2=1-(1/9)=8/9}}} and

{{{cos(theta)=sqrt(8/9)=(2sqrt(2))/3}}}

tan(theta) =sin(theta)/cos(theta)=(1/3)/(2sqrt(2)/3)=1/(2sqrt(2)

Done.