Question 429403
what are the linear factors of this polynomial: 
7x^3-39x^2-40x+132
----
{{{graph(400,300,-20,20,-150,150,7x^3-39x^2-40x+132)}}}

---------------------
Using synthetic division:
-2)....7....-39....-40....132
........7...-53.....66....|..0

Solve 7x^2-53x+66 = 0
x = [53 +- sqrt(53^2-4*7*66)]/(2*7)
---
x = [53 +- sqrt(961)]/14
---
x = [53+31]/14 or x = [53-31]/14
---
x = [64/14] or x = [22/14]
---
x = 32/7 or x = 11/7
----
Zeroes are at x= -2,32/7,11/7
------------------------
----
Cheers,
Stan H. 

--------------------------------------------------------------------------------