Question 429427
I presume the linear equation will have a strange polar representation.

From 5x = 5y we obtain x = y and {{{r*cos(theta) = r*sin(theta)}}}. We wish to isolate r.


Moving all terms to one side we get {{{r*cos(theta) - r*sin(theta) = 0}}} --> {{{r(cos(theta) - sin(theta)) = 0}}} and {{{r = 0/(cos(theta)-sin(theta))}}}. What's interesting about this graph is that when {{{cos(theta) - sin(theta) = 0}}} ({{{theta = pi/4 + k*pi}}}), we get an indeterminate form and r can equal anything. {{{0/0}}} can theoretically be equal to any number, which is why it is considered indeterminate instead of undefined.