Question 429347
A Ricoh copier can complete a job in 10 minutes.
 A xerox machine can do the same job in 12 minutes.
A worker needs a job completed in 5 minutes.
If both copiers work on the job at the same time, will the worker have the job done in time? 
 Explain with work shown.
:
Let t = time required with both copiers operating
Let the completed job = 1
:
Each copier will do a fraction of the job, the two factions must add up to 1
{{{t/10}}} + {{{t/12}}} = 1
To clear the denominators, multiply by 60, results:
6t + 5t = 60
11t = 60
t = {{{60/11}}}
t = 5.45 min, so not quite